Electricity

Electric circuits (Grade 12)

Internal resistance, terminal pd V = ε − Ir, series/parallel networks, and power P = IV = I²R = V²/R.

CAPS

Grade 12 · Physical Sciences (Physics) · Electricity

Physics is Physical Sciences Paper 1.

  • The paper

    Grade 12 Paper 1 covers Newton’s laws, momentum, work, energy and power, Doppler, electrostatics, electric circuits, electrodynamics and optical phenomena.

  • Working

    Write the formula as it appears on the data sheet, substitute with units, then the answer with the unit and the direction if it is a vector. A positive direction you chose must be stated when the sign matters.

  • The relation

    V = ε − I r. Terminal potential difference

  • How a marker reads it

    Lost volts = Ir. Never use ε as the pd across the external resistor when r is not negligible.

Paper 1 is 150 marks. The data sheet is allowed. A formula copied wrong cannot be saved by a tidy final number.

RA

Diagram

Worked example

A battery ε = 12 V, r = 1.0 Ω feeds a 5.0 Ω lamp. Find the current, terminal pd and power in the lamp.

Simplified approach

Total R = R + r. I = ε / (R+r). Terminal V = IR (external) = ε − Ir. Lamp power I²R.

Culture note

A taxi battery in a Durban rank feeding a weak interior lamp — internal resistance eats some of the 12 V.

Formulas

V=ε−I r

Terminal potential difference

P=I V=I² R=V²R

Electrical power

How to hunt the missing letter

Do not start by naming the letters. First hunt the missing one: copy every number you can see (Given). The letter with no number is Missing. The asking word is Find. The formula that still contains that letter is what you Calculate.

How to hunt: (1) Underline every number and its unit — those are Given. (2) Circle the asking word — find, calculate, how far, what is. That word names Find. (3) The letter the asking word names, which has no number yet, is Missing. (4) Write the formula with empty letters. Cross out every given letter. The letter still standing is what you Calculate.

  • ε

    emf

    How you spot this in the sentence

    When the sentence names the emf, that letter is ε. Copy the number next to it into Given. If the sentence never names it, ε is Missing. V = ε − I r when the battery supplies current.

    Example:Internal r is the battery; external R is the rest of the circuit.

  • P

    power

    How you spot this in the sentence

    When the sentence names the power, that letter is P. Copy the number next to it into Given. If the sentence never names it, P is Missing. P = I V = I² R = V² / R, in watts.

    Example:A 60 W bulb on 230 V: I=PV ≈ 0,26 A.

Exam tricks you must know

These are the moves markers look for — not shortcuts that skip the method, but the habits that earn the method mark.

  • List the five, then pick the equation that still has the missing letter

    How:Write a column: v_i, v_f, a, Δt, Δx. Tick every one that has a number. The unticked letter is Missing. Choose the SUVAT line that does not need a letter you do not have — do not start from the formula you remember first.

    When to use it:Any constant-acceleration question that names times, speeds or distances.

  • Use g = 9,8 unless the paper says take g = 10

    How:Copy g from the data sheet onto your given column first. If the instruction line says “take g = 10”, write that. Otherwise 9,8 m·s⁻². Using 10 when the paper did not say so loses the accuracy mark even if the method is right.

    When to use it:Free fall, projectiles, weight, and gravitational potential energy.

  • State “mechanical energy is conserved” in words before you substitute

    How:The method mark sits in the sentence, not in the algebra. Write: mechanical energy conserved because no non-conservative work (or friction is neglected). Then E_k + E_p at A = E_k + E_p at B. Then substitute.

    When to use it:Any conservation question, rollers, pendulums, or falling masses.

Step 1 / 6

Current

I=12(5+1)=2.0 A.

2.0 A

Why this step: We only do one job per line so a marker can follow the marks — and so you can find a slip without starting over.

4. Step-by-step working

  1. 01

    Current

    I=12(5+1)=2.0 A.

    2.0 A
  2. 02

    Terminal pd

    V=12−2.0(1.0)=10 V (also IR = 2×5 = 10 V).

    10 V
  3. 03

    Power

    P=I²R=4×5=20 W.

    20 W

More worked examples

Board walkthroughs on this topic. Open one, copy the working, then try the next.

Example 1 / 20

A battery (emf 12 V, internal resistance 1.0 Ω) is connected to a 3.0 Ω resistor in series with a parallel pair of 4 Ω and 4 Ω. Find the current from the battery, the terminal potential difference and the potential difference across the parallel pair.

4. Step-by-step working

  1. 01

    Parallel pair

    Rp=(4 × 4)(4 + 4)=2.00 Ω; Rext=3.0+2.00=5.00 Ω.

    Rext=5.00 Ω
  2. 02

    Current

    I=ε(Rext + r)=12(5.00 + 1.0)=2.00 A.

    I=2.00 A
  3. 03

    Potential differences

    Vterminal=IRext=2.00×5.00=10.0 V; Vp=2.00×2.00=4.00 V.

    V=10.0 V, Vp=4.00 V

How we got there

Read this like a teacher at the board. We go slowly, name every number, and say why we take each step.

Explain in another language · 11

1. What is the question asking?

Read the question twice. Circle the unknown. Underline every number and unit. The paper is asking: A battery (emf 12 V, internal resistance 1.0 Ω) is connected to a 3.0 Ω resistor in series with a parallel pair of 4 Ω and 4 Ω. Find the current from the battery, the terminal potential difference and the potential difference across the parallel pair.

In other words — as if you have never seen this before

If you have never seen this before: Reduce the external circuit to one resistance, use ε = I(R + r) for the current, then V = IR for each part. We will name a method in words, write the formula with no numbers, then substitute one line at a time.

2. What do we already know?

ε=12 V, r=1.0 Ω, R₁=3.0 Ω, R₂=4 Ω ∥ R₃=4 Ω.

3. Which method — and why this one?

Reduce the external circuit to one resistance, use ε = I(R + r) for the current, then V = IR for each part.

4. Step-by-step working

  1. 01 / 06

    Parallel pair

    Rp=(4 × 4)(4 + 4)=2.00 Ω; Rext=3.0+2.00=5.00 Ω.

    Rext=5.00 Ω

    Why this step: We only do one job per line so a marker can follow the marks — and so you can find a slip without starting over.

  2. 02 / 06

    Current

    I=ε(Rext + r)=12(5.00 + 1.0)=2.00 A.

    I=2.00 A

    Why this step: We only do one job per line so a marker can follow the marks — and so you can find a slip without starting over.

  3. 03 / 06

    Potential differences

    Vterminal=IRext=2.00×5.00=10.0 V; Vp=2.00×2.00=4.00 V.

    V=10.0 V, Vp=4.00 V

    Why this step: We only do one job per line so a marker can follow the marks — and so you can find a slip without starting over.

  4. 04 / 06

    Step G — Sense-check the size

    Ask: is this the kind of number a Grade 10–12 paper would want? A speed of 3 000 ms for a learner walking, or a probability bigger than 1, means a unit or algebra slip. Estimate first: round the numbers and do the sum in your head.

    Why this step: Markers write ‘unrealistic’ in the margin when the method is right but the size is wild. A 10-second head check often finds a missing 10² or a unit that never changed.

  5. 05 / 06

    Step F — Box the answer with its unit

    I = 2.00 A; V_terminal = 10.0 V; V_parallel = 4.00 V

    Why this step: A number without a unit is half a mark on a Physics paper, and a marker can miss a Maths answer that is buried in working.

  6. 06 / 06

    Step H — What the marker is looking for

    On an NSC memo you usually earn: (1) a method mark for naming the right formula or idea in words, (2) an accuracy mark for substituting the given numbers with units, (3) an accuracy mark for the boxed answer with its unit. Write those three lines even if you are unsure of the arithmetic — blank pages score zero.

    Why this step: First-timers chase the final number and leave the method blank. The memo still pays out for the idea and the substitution even when the last line is wrong.

5. The answer

I = 2.00 A; V_terminal = 10.0 V; V_parallel = 4.00 V

Copy onto your answer sheet — in this order

Formula: Rext=5.00 Ω

Answer: I = 2.00 A; V_terminal = 10.0 V; V_parallel = 4.00 V

6. Check it like a marker

Leaving out r makes the current too big. The terminal p.d. is always less than the emf while current flows.

7. A trap first-timers fall into

First-timers often grab the first formula they remember, mix units (cm with m, minutes with seconds), or drop a minus sign. Write the formula in words first: “this equals that, because…”

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